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Coordinate geometry and slope — SSAT Upper practice questions

Coordinate geometry and slope on the SSAT Upper Quantitative (Math) section covers points on a coordinate plane, distances between them, figures built from given vertices, and lines whose slope is known. A student has to find a distance, locate a point from an area condition, and use the slope formula to solve for a missing coordinate. Questions typically give labeled points and ask for a length, an x-coordinate, or an unknown y-value. Answer choices are numbers, sometimes fractions. Common traps are swapping rise and run, mixing which points belong to which segment, and treating a horizontal line as if its slope were not zero.

  • Section: Quantitative (Math) 50 questions on the paper
  • 91 practice questions in the app

Sample questions

Question 1

Points A(2,5)A(2, 5) and B(8,5)B(8, 5) are on a coordinate plane. What is the distance from AA to BB?

  1. A6
  2. B7
  3. C8
  4. D10
  5. E13
Show answer

Answer: A — 6

The horizontal distance is the difference in xx-coordinates: 82=68 - 2 = 6.

Question 2

In the coordinate plane, points A(1,2)A(1, 2), B(9,2)B(9, 2), and C(9,8)C(9, 8) are vertices of triangle ABCABC. Point DD lies on segment ABAB. If the area of triangle DBCDBC is 18 square units, what is the xx-coordinate of DD?

  1. A2
  2. B3
  3. C4
  4. D5
  5. E6
Show answer

Answer: B — 3

The height from CC to line ABAB is 82=68-2=6. If DD has xx-coordinate dd, then DB=9dDB=9-d. The area equation is 12(9d)(6)=18\dfrac{1}{2}(9-d)(6)=18, so d=3d=3.

Question 3

A line with slope 34-\dfrac{3}{4} contains the points (2,7)(-2, 7) and (6,t)(6, t). What is the value of tt?

  1. A-1
  2. B1
  3. C4
  4. D7
  5. E13
Show answer

Answer: B — 1

Use t76(2)=34\dfrac{t-7}{6-(-2)} = -\dfrac{3}{4}. Then t78=34\dfrac{t-7}{8} = -\dfrac{3}{4}, so t7=6t-7 = -6 and t=1t = 1.

Practice 91 Coordinate geometry and slope questions in the app

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